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Home My WebLink AboutStructuralDesign_RogueCreditUnion_V1Page 1 of 3 PROJECT: ROGUE CREDIT UNION DATE: PROJ. NO.: 48485A ENGINEER: CLIENT: ES&A SIGN &AWNING CO. V5.5 units; pounds, feet unless noted otherwise Applied Wind Loads; from ASCE 7-16 F=qz*G*Cf*Af with qz = 0.00256KzKztKdV2 (29.3.2 & 29.4) Cf=1.537 (Fig. 29.3-1)1.00 0 max. height= 25.0 1.0 Kzt=1.0 (26.8.2) (=1.0 unless unusual landscape)s= #### Kz=from table 28.3-1 Exposure= C 2 Kd=0.85 for signs (table 26.6-1)Lz= V= 105 mph G= 0.85 (26.9)weight= 3.550 kips s/h=1.000 MDL=0.00 k-ft B/s=0.57 Pole structure height at Wind Loads component section c.g.Kz qz Af shear Moment MW 1 7.50 0.850 20.4 212.0 5648 42363 2 17.33 0.874 21.0 66.0 1807 31316 3 19.83 0.900 21.6 5.1 142 2826 4 20.58 0.905 21.7 17.7 501 10303 5 23.083125 0.926 22.2 54.2 1572 36288 6 25.005 0.940 22.6 0.1 4 104 sums: 355.0 9674 123.20 (Mw)k-ft arm= 12.7 for s/h=1, add 10% (asce fig. 29.4-1):x 1.10 135.52 Pu=4.26 kip M= 135.52 k-ft M=sqrt(MDL2+Mw2) Mu=sqrt(1.2MDL2+1.0MW2) =135.52 k-ft Pole Design section; pipe Mu < IMn with Mn = fyZ fy=42 ksi ࢥ=0.9 H Mu(k-ft)t (in) Z USE at grade 135.52 0.375 53.7 12.75X0.375 Round. Hss, IMn=169 k-ft Footing Design footprint: round Z=1.3 IBC 1605.3.2 IBC Table 1806.2, sections 1806.3.4, 1807.3.2 S=(1.3x2x150 psf/ft) P= 7.55 kip S1 = S x d / 3 A = 2.34 x P / (S1 x b) S= 400 S1= 1218 d =0.5xA (1+ (1+4.36x h/A) ^.5) IBC 1807.3.2.1 A= 3.63 footing:4' - 0" dia. 9' - 2" deep Z req'd. (in) Size(in) 43.02 12 27.39 11/4/24 PRC pressure qz*G*Cf 26.64 28.21 28.36 29.01 29.46 Page 2 of 3 PROJECT: ROGUE CREDIT UNION DATE: PROJ. NO.: 48485A ENGINEER: CLIENT: ES&A SIGN & AWNING CO. building code; IBC 2012 units; pounds, feet unless noted otherwise Check HSS12.75X.375 for torsion and combined forces (AISC 14 H3) Pnet= 29.46 psf Area= 355 ft^2 WL= 10.46 kip Arm= 33.93 in (0.2* 14'-1.625") Tu = 354.8 k-in Fy = 42 ksi D = 12.75 in3 Fcr = 129.5 ksi (eq'n. H3-2a) t = 0.349 in3 or E = 29000 ksi Fcr = 78.8 ksi (eq'n. H3-2b) L = 120 in but not greater than: C = 82.10 in3 0.6 Fy = 25.2 ksi I = 0.9 ITn = I Fcr C = 1862 k-in OK Mr/Mc + (Tr/Tc)2 = 0.838 <1 OK (eq'n. H3-6) 11/4/2024 PRC Page 3 of 3